# Calculate the mass of calcium oxide and the volume of carbon dioxide formed when calcining 100 g

**Calculate the mass of calcium oxide and the volume of carbon dioxide formed when calcining 100 g of limestone containing 10% impurities**

The decomposition reaction of calcium carbonate is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

One mole of calcium carbonate forms one mole of calcium oxide and carbon monoxide.

Determine the mass of pure calcium carbonate.

m CaCO3 = 100 x 90% = 90 grams;

Determine the amount of substance in 90 grams of calcium carbonate.

Its molar mass is:

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

The amount of substance will be:

N CaCO3 = 90/100 = 0.9 mol;

The same amount of carbon monoxide and calcium oxide will be obtained.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Let’s determine the volume of carbon dioxide:

V CO2 = 0.9 x 22.4 = 20.16 liters;

The molar mass of calcium oxide is:

M CaO = 40 + 16 = 56 grams / mol;

The mass of calcium oxide will be:

m CaO = 56 x 0.9 = 50.4 grams;